接外包,有相关需求的可以联系我:Telegram | Email

Split Array Largest Sum | Binary Search

该文章创建(更新)于03/4/2022,请注意文章的时效性!

文章目录[隐藏]

Given an array nums which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays.

Write an algorithm to minimize the largest sum among these m subarrays.

Solution

Binary Search

Code

  • submit code
class Solution:
    def splitArray(self, nums: List[int], m: int) -> int:

        left = max(nums)
        right = sum(nums)

        while left < right:
            mid = left + (right - left)  // 2
            tmp = self.spilt(nums,mid)
            if(tmp <= m):
                right = mid
            elif(tmp > m):
                left = mid + 1

        return left


    # 若最大子数组和为ma,计算nums至少被分成几个子数组
    def spilt(self,nums,ma):
        count = 0
        Sum = 0

        i = 0
        while i < len(nums):
            Sum += nums[i]
            if(Sum > ma):
                Sum = 0
                count += 1
                continue
            # elif(Sum == ma):
            #     Sum = 0
            #     count += 1
            elif(Sum <= ma and i == len(nums) - 1):
                count += 1
            i += 1

        return count
  • full code
class Solution:
    def splitArray(self, nums, m):

        left = max(nums)
        right = sum(nums)
        print("left:\t" + str(left) + "\tright: " + str(right))

        while left < right:
            print("left:\t" + str(left))
            # mid = left + (right - left) // 2
            mid = left + int((right - left) / 2)
            tmp  = self.spilt(nums,mid)
            print("tmp:\t" + str(tmp))
            if tmp <= m:
                right = mid
            elif tmp > m:
                left = mid + 1
        return left

    # 若最大子数组和为ma,计算nums至少被分成几个子数组
    def spilt(self,nums,ma):
        count = 0
        Sum = 0

        i = 0
        # print("ma:\t" + str(ma))
        while i < len(nums):
            Sum += nums[i]
            # print("i:\t" + str(i) + "\tSum:\t" + str(Sum))
            if(Sum > ma):
                Sum = 0
                count += 1
                # print("count:\t" + str(count))
                continue
            # elif(Sum == ma):
            #     Sum = 0
            #     count += 1
            elif(Sum <= ma and i == len(nums) - 1):
                count += 1
            # print("count:\t" + str(count))
            # print("---------------------------------\n")
            i += 1

        return count

S = Solution()
# nums = [7,2,5,10,8]
# m = 2
# nums = [1,2,3,4,5]
# m = 2
# nums = [5334,6299,4199,9663,8945,3566,9509,3124,6026,6250,7475,5420,9201,9501,38,5897,4411,6638,9845,161,9563,8854,3731,5564,5331,4294,3275,1972,1521,2377,3701,6462,6778,187,9778,758,550,7510,6225,8691,3666,4622,9722,8011,7247,575,5431,4777,4032,8682,5888,8047,3562,9462,6501,7855,505,4675,6973,493,1374,3227,1244,7364,2298,3244,8627,5102,6375,8653,1820,3857,7195,7830,4461,7821,5037,2918,4279,2791,1500,9858,6915,5156,970,1471,5296,1688,578,7266,4182,1430,4985,5730,7941,3880,607,8776,1348,2974,1094,6733,5177,4975,5421,8190,8255,9112,8651,2797,335,8677,3754,893,1818,8479,5875,1695,8295,7993,7037,8546,7906,4102,7279,1407,2462,4425,2148,2925,3903,5447,5893,3534,3663,8307,8679,8474,1202,3474,2961,1149,7451,4279,7875,5692,6186,8109,7763,7798,2250,2969,7974,9781,7741,4914,5446,1861,8914,2544,5683,8952,6745,4870,1848,7887,6448,7873,128,3281,794,1965,7036,8094,1211,9450,6981,4244,2418,8610,8681,2402,2904,7712,3252,5029,3004,5526,6965,8866,2764,600,631,9075,2631,3411,2737,2328,652,494,6556,9391,4517,8934,8892,4561,9331,1386,4636,9627,5435,9272,110,413,9706,5470,5008,1706,7045,9648,7505,6968,7509,3120,7869,6776,6434,7994,5441,288,492,1617,3274,7019,5575,6664,6056,7069,1996,9581,3103,9266,2554,7471,4251,4320,4749,649,2617,3018,4332,415,2243,1924,69,5902,3602,2925,6542,345,4657,9034,8977,6799,8397,1187,3678,4921,6518,851,6941,6920,259,4503,2637,7438,3893,5042,8552,6661,5043,9555,9095,4123,142,1446,8047,6234,1199,8848,5656,1910,3430,2843,8043,9156,7838,2332,9634,2410,2958,3431,4270,1420,4227,7712,6648,1607,1575,3741,1493,7770,3018,5398,6215,8601,6244,7551,2587,2254,3607,1147,5184,9173,8680,8610,1597,1763,7914,3441,7006,1318,7044,7267,8206,9684,4814,9748,4497,2239]
# m = 9

nums = [5,2,4,1,3,6,0]
m = 4
print("#####################################")
print(S.splitArray(nums,m))

要不赞赏一下?

微信
支付宝
PayPal
Bitcoin

版权声明 | Copyright

除非特别说明,本博客所有作品均采用知识共享署名-非商业性使用-禁止演绎 4.0 国际许可协议进行许可。转载请注明转自-
https://www.emperinter.info/2022/03/04/split-array-largest-sum/


要不聊聊?

我相信你准备留下的内容是经过思考的!【勾选防爬虫,未勾选无法留言】

*

*



YouTube | B站

微信公众号

👉 NewsLetter ❤️ 邮箱订阅 👈

优惠码

阿里云国际版20美元
Vultr10美元
搬瓦工 | Bandwagon应该有折扣吧?
Just My SocksJMS9272283 【注意手动复制去跳转】
域名 | namesiloemperinter(1美元)
币安 币安