Given a string s, find the length of the longest substring without repeating characters.

• https://leetcode.com/problems/longest-substring-without-repeating-characters/

sliding windows, The most import things is how to get The max.

• submit code

class Solution:
    def lengthOfLongestSubstring(self, s: str) -> int:
        left = 0
        right = 0

        window_dict = {}

        max = 0

        tmp = ""

        while left < len(s):
            INPUT = s[left]
            left += 1
            tmp  += INPUT

            window_dict[INPUT] = window_dict.get(INPUT,0) + 1

            if (max < len(tmp) and window_dict.get(INPUT) == 1):
                max = len(tmp)

            while(window_dict.get(INPUT) > 1):
                OUTPUT = s[right]
                right += 1
                tmp = tmp[1:]

                if(max < len(tmp)):
                    max = len(tmp) - 1

                window_dict[OUTPUT] = window_dict.get(OUTPUT) - 1

        return  max

• full code

class Solution:
    def lengthOfLongestSubstring(self, s: str) -> int:
        # if(len(s) == 1):
        #     return 1

        left = 0
        right = 0

        window_dict = {}

        max = 0

        tmp = ""

        while left < len(s):
            INPUT = s[left]
            left += 1
            tmp += INPUT

            # if (max < len(tmp)):
            #     max = len(tmp)
            print("tmp:" + tmp)

            window_dict[INPUT] = window_dict.get(INPUT,0) + 1

            if (max < len(tmp) and window_dict.get(INPUT) == 1):
                max = len(tmp)

            while(window_dict.get(INPUT) > 1):
                print("__________________desec__________________")
                OUTPUT = s[right]
                right += 1

                if( max < len(tmp)):
                    max = len(tmp) - 1

                tmp = tmp[1:]
                window_dict[OUTPUT] = window_dict.get(OUTPUT) - 1

        return  max


S = Solution()
s = ""
s = "a"
# s = " a"
# s = "abcabcbb"
print(S.lengthOfLongestSubstring(s))

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